Base | Representation |
---|---|
bin | 1100110101011101010100… |
… | …1111010000010110110000 |
3 | 1211222010221112102002112022 |
4 | 3031113111033100112300 |
5 | 3322204443022113040 |
6 | 50003114055251012 |
7 | 2654412011133050 |
oct | 315272517202660 |
9 | 54863845362468 |
10 | 14112545113520 |
11 | 45511078921a7 |
12 | 16bb132979a68 |
13 | 7b4a65817489 |
14 | 36b09d687560 |
15 | 1971766836b5 |
hex | cd5d53d05b0 |
14112545113520 has 160 divisors (see below), whose sum is σ = 39745292709888. Its totient is φ = 4549328400384.
The previous prime is 14112545113507. The next prime is 14112545113573. The reversal of 14112545113520 is 2531154521141.
It is a happy number.
14112545113520 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×141125451135202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8604137 + ... + 10112183.
Almost surely, 214112545113520 is an apocalyptic number.
14112545113520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14112545113520, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19872646354944).
14112545113520 is an abundant number, since it is smaller than the sum of its proper divisors (25632747596368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112545113520 is a wasteful number, since it uses less digits than its factorization.
14112545113520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1509067 (or 1509061 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 14112545113520 its reverse (2531154521141), we get a palindrome (16643699634661).
The spelling of 14112545113520 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, one hundred thirteen thousand, five hundred twenty".
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