Base | Representation |
---|---|
bin | 1100110101011101010101… |
… | …0000000011110101000000 |
3 | 1211222010221112210210201220 |
4 | 3031113111100003311000 |
5 | 3322204443100334402 |
6 | 50003114103555040 |
7 | 2654412013001526 |
oct | 315272520036500 |
9 | 54863845723656 |
10 | 14112545324352 |
11 | 4551107a16642 |
12 | 16bb132a5ba80 |
13 | 7b4a6588c427 |
14 | 36b09d700316 |
15 | 1971766c5dbc |
hex | cd5d5403d40 |
14112545324352 has 28 divisors (see below), whose sum is σ = 37339442837856. Its totient is φ = 4704181774720.
The previous prime is 14112545324299. The next prime is 14112545324369. The reversal of 14112545324352 is 25342354521141.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36751419924 + ... + 36751420307.
Almost surely, 214112545324352 is an apocalyptic number.
14112545324352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14112545324352 is an abundant number, since it is smaller than the sum of its proper divisors (23226897513504).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112545324352 is an equidigital number, since it uses as much as digits as its factorization.
14112545324352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73502840246 (or 73502840236 counting only the distinct ones).
The product of its digits is 576000, while the sum is 42.
Adding to 14112545324352 its reverse (25342354521141), we get a palindrome (39454899845493).
The spelling of 14112545324352 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, three hundred twenty-four thousand, three hundred fifty-two".
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