141132404125200 has 120 divisors (see below), whose sum is σ = 454236761592736. Its totient is φ = 37456941312000.

The previous prime is 141132404125199. The next prime is 141132404125211. The reversal of 141132404125200 is 2521404231141.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-3 number, since 3×141132404125200³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 278444281 + ... + 278950680.

Almost surely, 2^{141132404125200} is an apocalyptic number.

141132404125200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141132404125200 is an abundant number, since it is smaller than the sum of its proper divisors (313104357467536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132404125200 is a wasteful number, since it uses less digits than its factorization.

141132404125200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 557395193 (or 557395182 counting only the distinct ones).

The product of its (nonzero) digits is 7680, while the sum is 30.

Adding to 141132404125200 its reverse (2521404231141), we get a palindrome (143653808356341).

The spelling of 141132404125200 in words is "one hundred forty-one trillion, one hundred thirty-two billion, four hundred four million, one hundred twenty-five thousand, two hundred".