Base | Representation |
---|---|
bin | 100000000110000001011001… |
… | …110100111001100101001110 |
3 | 200111202221012122100221211022 |
4 | 200012001121310321211032 |
5 | 122000110341414132220 |
6 | 1220112003452154142 |
7 | 41505563050011440 |
oct | 4006013164714516 |
9 | 614687178327738 |
10 | 141151312255310 |
11 | 40a7aa31a63105 |
12 | 139b80a0a68952 |
13 | 609b686094906 |
14 | 26bda8d4b6490 |
15 | 114ba09b43925 |
hex | 806059d3994e |
141151312255310 has 32 divisors (see below), whose sum is σ = 305650961879040. Its totient is φ = 45847644280992.
The previous prime is 141151312255279. The next prime is 141151312255397. The reversal of 141151312255310 is 13552213151141.
It is a super-2 number, since 2×1411513122553102 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53064401774 + ... + 53064404433.
It is an arithmetic number, because the mean of its divisors is an integer number (9551592558720).
Almost surely, 2141151312255310 is an apocalyptic number.
141151312255310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
141151312255310 is an abundant number, since it is smaller than the sum of its proper divisors (164499649623730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141151312255310 is a wasteful number, since it uses less digits than its factorization.
141151312255310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106128806240.
The product of its (nonzero) digits is 18000, while the sum is 35.
The spelling of 141151312255310 in words is "one hundred forty-one trillion, one hundred fifty-one billion, three hundred twelve million, two hundred fifty-five thousand, three hundred ten".
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