Base | Representation |
---|---|
bin | 1100110110001011101110… |
… | …1100010101100111111110 |
3 | 1212000100002122011121112112 |
4 | 3031202323230111213332 |
5 | 3322411000331302200 |
6 | 50012534105334022 |
7 | 2655332463112052 |
oct | 315427354254776 |
9 | 55010078147475 |
10 | 14125001431550 |
11 | 455641a085309 |
12 | 170162a497312 |
13 | 7b5c9c37b669 |
14 | 36b921b29c62 |
15 | 197654ede535 |
hex | cd8bbb159fe |
14125001431550 has 48 divisors (see below), whose sum is σ = 27908556706800. Its totient is φ = 5300326172160.
The previous prime is 14125001431393. The next prime is 14125001431559. The reversal of 14125001431550 is 5513410052141.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14125001431559) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26803625 + ... + 27325524.
It is an arithmetic number, because the mean of its divisors is an integer number (581428264725).
Almost surely, 214125001431550 is an apocalyptic number.
14125001431550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14125001431550 is a deficient number, since it is larger than the sum of its proper divisors (13783555275250).
14125001431550 is a wasteful number, since it uses less digits than its factorization.
14125001431550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54129485 (or 54129480 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 14125001431550 its reverse (5513410052141), we get a palindrome (19638411483691).
The spelling of 14125001431550 in words is "fourteen trillion, one hundred twenty-five billion, one million, four hundred thirty-one thousand, five hundred fifty".
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