Base | Representation |
---|---|
bin | 1100110111010111000110… |
… | …0110100111011011111100 |
3 | 1212002021022121220200121010 |
4 | 3031311301212213123330 |
5 | 3323223414203113030 |
6 | 50030121435435220 |
7 | 2656650031552422 |
oct | 315656146473374 |
9 | 55067277820533 |
10 | 14145233254140 |
11 | 4563a6145204a |
12 | 1705535bb5b10 |
13 | 7b7b74aa3011 |
14 | 36c8c0b19112 |
15 | 197e3b29d6b0 |
hex | cdd719a76fc |
14145233254140 has 48 divisors (see below), whose sum is σ = 40255942517280. Its totient is φ = 3710225114880.
The previous prime is 14145233254133. The next prime is 14145233254151. The reversal of 14145233254140 is 4145233254141.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1932405255 + ... + 1932412574.
It is an arithmetic number, because the mean of its divisors is an integer number (838665469110).
Almost surely, 214145233254140 is an apocalyptic number.
14145233254140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14145233254140 is an abundant number, since it is smaller than the sum of its proper divisors (26110709263140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14145233254140 is a wasteful number, since it uses less digits than its factorization.
14145233254140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3864817902 (or 3864817900 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 39.
Subtracting from 14145233254140 its reverse (4145233254141), we obtain a palindrome (9999999999999).
The spelling of 14145233254140 in words is "fourteen trillion, one hundred forty-five billion, two hundred thirty-three million, two hundred fifty-four thousand, one hundred forty".
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