Base | Representation |
---|---|
bin | 101010010100011… |
… | …1101110100011000 |
3 | 10122222000202020200 |
4 | 1110220331310120 |
5 | 10402011300422 |
6 | 352524022200 |
7 | 50122004622 |
oct | 12450756430 |
9 | 3588022220 |
10 | 1420025112 |
11 | 669626980 |
12 | 337691960 |
13 | 19827045c |
14 | d6845c12 |
15 | 849ed2ac |
hex | 54a3dd18 |
1420025112 has 96 divisors (see below), whose sum is σ = 4226040000. Its totient is φ = 427181760.
The previous prime is 1420025081. The next prime is 1420025137. The reversal of 1420025112 is 2115200241.
It is a super-2 number, since 2×14200251122 = 4032942637421225088, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 103639 + ... + 116537.
It is an arithmetic number, because the mean of its divisors is an integer number (44021250).
Almost surely, 21420025112 is an apocalyptic number.
1420025112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1420025112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2113020000).
1420025112 is an abundant number, since it is smaller than the sum of its proper divisors (2806014888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1420025112 is a wasteful number, since it uses less digits than its factorization.
1420025112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13061 (or 13054 counting only the distinct ones).
The product of its (nonzero) digits is 160, while the sum is 18.
The square root of 1420025112 is about 37683.2205630039. The cubic root of 1420025112 is about 1123.9974903166.
Adding to 1420025112 its reverse (2115200241), we get a palindrome (3535225353).
The spelling of 1420025112 in words is "one billion, four hundred twenty million, twenty-five thousand, one hundred twelve".
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