Base | Representation |
---|---|
bin | 1100111011010111101111… |
… | …0101011111101000000000 |
3 | 1212022212010202202122221101 |
4 | 3032311323311133220000 |
5 | 3330341011321400300 |
6 | 50121513440104144 |
7 | 2664636152633461 |
oct | 316657365375000 |
9 | 55285122678841 |
10 | 14214124403200 |
11 | 45901a3733a87 |
12 | 1716961605054 |
13 | 7c150358b147 |
14 | 371d7836ad68 |
15 | 199b1e37ab6a |
hex | ced7bd5fa00 |
14214124403200 has 120 divisors (see below), whose sum is σ = 36430970283180. Its totient is φ = 5489592729600.
The previous prime is 14214124402931. The next prime is 14214124403309. The reversal of 14214124403200 is 230442141241.
It can be written as a sum of positive squares in 6 ways, for example, as 5101743759616 + 9112380643584 = 2258704^2 + 3018672^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18774981 + ... + 19517380.
Almost surely, 214214124403200 is an apocalyptic number.
14214124403200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14214124403200 is an abundant number, since it is smaller than the sum of its proper divisors (22216845879980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14214124403200 is an equidigital number, since it uses as much as digits as its factorization.
14214124403200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38292418 (or 38292397 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 14214124403200 its reverse (230442141241), we get a palindrome (14444566544441).
The spelling of 14214124403200 in words is "fourteen trillion, two hundred fourteen billion, one hundred twenty-four million, four hundred three thousand, two hundred".
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