Base | Representation |
---|---|
bin | 1100111100011110000110… |
… | …1001100010001111011000 |
3 | 1212101122220002212222221201 |
4 | 3033013201221202033120 |
5 | 3331143202134212100 |
6 | 50134320003443544 |
7 | 2666205213236554 |
oct | 317074151421730 |
9 | 55348802788851 |
10 | 14233012413400 |
11 | 45982064a9670 |
12 | 171a5530865b4 |
13 | 7c3223777941 |
14 | 372c4aab2864 |
15 | 19a37769336a |
hex | cf1e1a623d8 |
14233012413400 has 96 divisors (see below), whose sum is σ = 36207218951280. Its totient is φ = 5160282624000.
The previous prime is 14233012413371. The next prime is 14233012413407. The reversal of 14233012413400 is 431421033241.
It is a happy number.
14233012413400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14233012413407) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8857341 + ... + 10340140.
Almost surely, 214233012413400 is an apocalyptic number.
14233012413400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14233012413400 is an abundant number, since it is smaller than the sum of its proper divisors (21974206537880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14233012413400 is a wasteful number, since it uses less digits than its factorization.
14233012413400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19197845 (or 19197836 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 14233012413400 its reverse (431421033241), we get a palindrome (14664433446641).
The spelling of 14233012413400 in words is "fourteen trillion, two hundred thirty-three billion, twelve million, four hundred thirteen thousand, four hundred".
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