Base | Representation |
---|---|
bin | 10100110001000010110… |
… | …111100011010111010100 |
3 | 12001102110122020001010220 |
4 | 110301002313203113110 |
5 | 141340100024020200 |
6 | 3011324515314340 |
7 | 205046440241031 |
oct | 24610267432724 |
9 | 5042418201126 |
10 | 1427051001300 |
11 | 5002330a5a11 |
12 | 1b06a45ab9b0 |
13 | a4755033812 |
14 | 4d0d9126388 |
15 | 271c2e1b4a0 |
hex | 14c42de35d4 |
1427051001300 has 72 divisors (see below), whose sum is σ = 4135897535616. Its totient is φ = 379905154560.
The previous prime is 1427051001283. The next prime is 1427051001319. The reversal of 1427051001300 is 31001507241.
It is a super-2 number, since 2×14270510013002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3832924 + ... + 4188723.
It is an arithmetic number, because the mean of its divisors is an integer number (57443021328).
Almost surely, 21427051001300 is an apocalyptic number.
1427051001300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1427051001300 is an abundant number, since it is smaller than the sum of its proper divisors (2708846534316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1427051001300 is a wasteful number, since it uses less digits than its factorization.
1427051001300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8022257 (or 8022250 counting only the distinct ones).
The product of its (nonzero) digits is 840, while the sum is 24.
Adding to 1427051001300 its reverse (31001507241), we get a palindrome (1458052508541).
The spelling of 1427051001300 in words is "one trillion, four hundred twenty-seven billion, fifty-one million, one thousand, three hundred".
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