Base | Representation |
---|---|
bin | 100000011110111100100111… |
… | …111100000011010000000000 |
3 | 200201211200101110011122202220 |
4 | 200132330213330003100000 |
5 | 122211141303302021344 |
6 | 1223502520430411040 |
7 | 42043411150001022 |
oct | 4036744774032000 |
9 | 621750343148686 |
10 | 142864167220224 |
11 | 41580397a3103a |
12 | 14034048660a80 |
13 | 6194057b1aca8 |
14 | 273c93c1d8012 |
15 | 117b358cb5c19 |
hex | 81ef27f03400 |
142864167220224 has 88 divisors (see below), whose sum is σ = 380793237359808. Its totient is φ = 47620370350080.
The previous prime is 142864167220211. The next prime is 142864167220253. The reversal of 142864167220224 is 422022761468241.
142864167220224 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1428641672202243 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150598909 + ... + 151544579.
Almost surely, 2142864167220224 is an apocalyptic number.
It is an amenable number.
142864167220224 is an abundant number, since it is smaller than the sum of its proper divisors (237929070139584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142864167220224 is an equidigital number, since it uses as much as digits as its factorization.
142864167220224 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 994871 (or 994853 counting only the distinct ones).
The product of its (nonzero) digits is 4128768, while the sum is 51.
The spelling of 142864167220224 in words is "one hundred forty-two trillion, eight hundred sixty-four billion, one hundred sixty-seven million, two hundred twenty thousand, two hundred twenty-four".
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