Base | Representation |
---|---|
bin | 1101000001000100100001… |
… | …1100101110100010110100 |
3 | 1212200012220010111121222120 |
4 | 3100101020130232202310 |
5 | 3333442032402124000 |
6 | 50234510254555540 |
7 | 3005003566123101 |
oct | 320211034564264 |
9 | 55605803447876 |
10 | 14312046520500 |
11 | 4618783168053 |
12 | 173192b508bb0 |
13 | 7ca80a754aa1 |
14 | 3769c745baa8 |
15 | 19c450e6b6a0 |
hex | d044872e8b4 |
14312046520500 has 96 divisors (see below), whose sum is σ = 41704489008000. Its totient is φ = 3813999078400.
The previous prime is 14312046520469. The next prime is 14312046520543. The reversal of 14312046520500 is 502564021341.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 934077 + ... + 5431076.
It is an arithmetic number, because the mean of its divisors is an integer number (434421760500).
Almost surely, 214312046520500 is an apocalyptic number.
14312046520500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14312046520500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20852244504000).
14312046520500 is an abundant number, since it is smaller than the sum of its proper divisors (27392442487500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14312046520500 is a wasteful number, since it uses less digits than its factorization.
14312046520500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6366674 (or 6366662 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
The spelling of 14312046520500 in words is "fourteen trillion, three hundred twelve billion, forty-six million, five hundred twenty thousand, five hundred".
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