143131311134040 has 64 divisors (see below), whose sum is σ = 443245350620160. Its totient is φ = 36937112549760.

The previous prime is 143131311133997. The next prime is 143131311134083. The reversal of 143131311134040 is 40431113131341.

It is an interprime number because it is at equal distance from previous prime (143131311133997) and next prime (143131311134083).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 143131311133989 and 143131311134007.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19238075734 + ... + 19238083173.

It is an arithmetic number, because the mean of its divisors is an integer number (6925708603440).

Almost surely, 2^{143131311134040} is an apocalyptic number.

143131311134040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143131311134040 is an abundant number, since it is smaller than the sum of its proper divisors (300114039486120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143131311134040 is a wasteful number, since it uses less digits than its factorization.

143131311134040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38476158952 (or 38476158948 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 143131311134040 its reverse (40431113131341), we get a palindrome (183562424265381).

The spelling of 143131311134040 in words is "one hundred forty-three trillion, one hundred thirty-one billion, three hundred eleven million, one hundred thirty-four thousand, forty".