14313763480650 has 96 divisors (see below), whose sum is σ = 36460228354368. Its totient is φ = 3713567731200.

The previous prime is 14313763480609. The next prime is 14313763480691. The reversal of 14313763480650 is 5608436731341.

It is an interprime number because it is at equal distance from previous prime (14313763480609) and next prime (14313763480691).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14313763480593 and 14313763480602.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 81569505 + ... + 81744795.

It is an arithmetic number, because the mean of its divisors is an integer number (379794045358).

Almost surely, 2^{14313763480650} is an apocalyptic number.

14313763480650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14313763480650 is an abundant number, since it is smaller than the sum of its proper divisors (22146464873718).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14313763480650 is a wasteful number, since it uses less digits than its factorization.

14313763480650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190056 (or 190051 counting only the distinct ones).

The product of its (nonzero) digits is 4354560, while the sum is 51.

The spelling of 14313763480650 in words is "fourteen trillion, three hundred thirteen billion, seven hundred sixty-three million, four hundred eighty thousand, six hundred fifty".