Base | Representation |
---|---|
bin | 1000010101111000100… |
… | …0110111111000100101 |
3 | 111200220202021012220211 |
4 | 2011132020313320211 |
5 | 4322001201231000 |
6 | 145500501255421 |
7 | 13232302665004 |
oct | 2053610677045 |
9 | 450822235824 |
10 | 143313305125 |
11 | 55862696341 |
12 | 23937404571 |
13 | 1068c152383 |
14 | 6d176acc3b |
15 | 3adba517ba |
hex | 215e237e25 |
143313305125 has 32 divisors (see below), whose sum is σ = 182449013760. Its totient is φ = 112352011200.
The previous prime is 143313305117. The next prime is 143313305131. The reversal of 143313305125 is 521503313341.
It is a happy number.
143313305125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 143313305125 - 23 = 143313305117 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5678284 + ... + 5703466.
It is an arithmetic number, because the mean of its divisors is an integer number (5701531680).
Almost surely, 2143313305125 is an apocalyptic number.
It is an amenable number.
143313305125 is a deficient number, since it is larger than the sum of its proper divisors (39135708635).
143313305125 is an equidigital number, since it uses as much as digits as its factorization.
143313305125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26110 (or 26100 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 143313305125 its reverse (521503313341), we get a palindrome (664816618466).
The spelling of 143313305125 in words is "one hundred forty-three billion, three hundred thirteen million, three hundred five thousand, one hundred twenty-five".
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