Base | Representation |
---|---|
bin | 1101000010001111000001… |
… | …1010101010100010111110 |
3 | 1212202010111211002020200112 |
4 | 3100203300122222202332 |
5 | 3334304011332440220 |
6 | 50252014511230022 |
7 | 3006312264354650 |
oct | 320436032524276 |
9 | 55663454066615 |
10 | 14332044421310 |
11 | 4626205492a00 |
12 | 1735790818312 |
13 | 7cc6768760a5 |
14 | 3779633586d0 |
15 | 19cc219205c5 |
hex | d08f06aa8be |
14332044421310 has 96 divisors (see below), whose sum is σ = 32420716425216. Its totient is φ = 4465240401600.
The previous prime is 14332044421307. The next prime is 14332044421327. The reversal of 14332044421310 is 1312444023341.
It is a super-2 number, since 2×143320444213102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 19725539 + ... + 20439201.
It is an arithmetic number, because the mean of its divisors is an integer number (337715796096).
Almost surely, 214332044421310 is an apocalyptic number.
14332044421310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14332044421310 is an abundant number, since it is smaller than the sum of its proper divisors (18088672003906).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14332044421310 is a wasteful number, since it uses less digits than its factorization.
14332044421310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 716070 (or 716059 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 14332044421310 its reverse (1312444023341), we get a palindrome (15644488444651).
The spelling of 14332044421310 in words is "fourteen trillion, three hundred thirty-two billion, forty-four million, four hundred twenty-one thousand, three hundred ten".
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