Base | Representation |
---|---|
bin | 1000011000010010111… |
… | …1011110111101010010 |
3 | 111202120212221112112220 |
4 | 2012010233132331102 |
5 | 4324313001221400 |
6 | 150045035001510 |
7 | 13254325656060 |
oct | 2060457367522 |
9 | 452525845486 |
10 | 143960960850 |
11 | 56065233703 |
12 | 23a98299296 |
13 | 10763395305 |
14 | 6d796dd030 |
15 | 3b288347a0 |
hex | 2184bdef52 |
143960960850 has 96 divisors (see below), whose sum is σ = 408150352896. Its totient is φ = 32895374400.
The previous prime is 143960960831. The next prime is 143960960851. The reversal of 143960960850 is 58069069341.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 143960960793 and 143960960802.
It is not an unprimeable number, because it can be changed into a prime (143960960851) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3768345 + ... + 3806355.
It is an arithmetic number, because the mean of its divisors is an integer number (4251566176).
Almost surely, 2143960960850 is an apocalyptic number.
143960960850 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143960960850 is an abundant number, since it is smaller than the sum of its proper divisors (264189392046).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143960960850 is a wasteful number, since it uses less digits than its factorization.
143960960850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41640 (or 41635 counting only the distinct ones).
The product of its (nonzero) digits is 1399680, while the sum is 51.
The spelling of 143960960850 in words is "one hundred forty-three billion, nine hundred sixty million, nine hundred sixty thousand, eight hundred fifty".
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