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14729304066047 is a prime number
BaseRepresentation
bin1101011001010110111011…
…1011111100011111111111
31221011002220112012010221222
43112111232323330133333
53412311103320103142
651154314320143555
73050104612545014
oct326255673743777
957132815163858
1014729304066047
11476973217588a
12179a77a167bbb
1382ac7653b52c
1438cc8b5c170b
151a8222961bd2
hexd656eefc7ff

14729304066047 has 2 divisors, whose sum is σ = 14729304066048. Its totient is φ = 14729304066046.

The previous prime is 14729304065951. The next prime is 14729304066049. The reversal of 14729304066047 is 74066040392741.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14729304066047 - 210 = 14729304065023 is a prime.

Together with 14729304066049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14729304066047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14729304066049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7364652033023 + 7364652033024.

It is an arithmetic number, because the mean of its divisors is an integer number (7364652033024).

Almost surely, 214729304066047 is an apocalyptic number.

14729304066047 is a deficient number, since it is larger than the sum of its proper divisors (1).

14729304066047 is an equidigital number, since it uses as much as digits as its factorization.

14729304066047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 53.

The spelling of 14729304066047 in words is "fourteen trillion, seven hundred twenty-nine billion, three hundred four million, sixty-six thousand, forty-seven".