Base | Representation |
---|---|
bin | 1000101110110110001… |
… | …0111000011010110000 |
3 | 112100012202020120211120 |
4 | 2023231202320122300 |
5 | 4424212120412430 |
6 | 152525433342240 |
7 | 13560330635445 |
oct | 2135542703260 |
9 | 470182216746 |
10 | 150014232240 |
11 | 5869113a034 |
12 | 250a7567980 |
13 | 111b94c34c2 |
14 | 73916179cc |
15 | 3d7ee91610 |
hex | 22ed8b86b0 |
150014232240 has 160 divisors (see below), whose sum is σ = 485496158400. Its totient is φ = 38269808640.
The previous prime is 150014232191. The next prime is 150014232283. The reversal of 150014232240 is 42232410051.
150014232240 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1500142322403 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 150014232240.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 659770 + ... + 857510.
It is an arithmetic number, because the mean of its divisors is an integer number (3034350990).
Almost surely, 2150014232240 is an apocalyptic number.
150014232240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 150014232240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242748079200).
150014232240 is an abundant number, since it is smaller than the sum of its proper divisors (335481926160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
150014232240 is a wasteful number, since it uses less digits than its factorization.
150014232240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197895 (or 197889 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 24.
Adding to 150014232240 its reverse (42232410051), we get a palindrome (192246642291).
The spelling of 150014232240 in words is "one hundred fifty billion, fourteen million, two hundred thirty-two thousand, two hundred forty".
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