Base | Representation |
---|---|
bin | 1000101110111010101… |
… | …0100010100101010100 |
3 | 112100021001120221220210 |
4 | 2023232222202211110 |
5 | 4424231423022142 |
6 | 152531344125420 |
7 | 13560646414143 |
oct | 2135652424524 |
9 | 470231527823 |
10 | 150033017172 |
11 | 586a07aa475 |
12 | 250b1906870 |
13 | 111c036c84c |
14 | 7393d0775a |
15 | 3d8195249c |
hex | 22eeaa2954 |
150033017172 has 24 divisors (see below), whose sum is σ = 368502148000. Its totient is φ = 47378847456.
The previous prime is 150033017171. The next prime is 150033017261. The reversal of 150033017172 is 271710330051.
150033017172 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1500330171723 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150033017171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 329019547 + ... + 329020002.
Almost surely, 2150033017172 is an apocalyptic number.
150033017172 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
150033017172 is an abundant number, since it is smaller than the sum of its proper divisors (218469130828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
150033017172 is a wasteful number, since it uses less digits than its factorization.
150033017172 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658039575 (or 658039573 counting only the distinct ones).
The product of its (nonzero) digits is 4410, while the sum is 30.
The spelling of 150033017172 in words is "one hundred fifty billion, thirty-three million, seventeen thousand, one hundred seventy-two".
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