Search a number
-
+
150099253 is a prime number
BaseRepresentation
bin10001111001001…
…01010100110101
3101110102211110121
420330211110311
5301411134003
622521051541
73501552103
oct1074452465
9343384417
10150099253
11777aa877
1242326bb1
1325135135
1415d12c73
15d29dcbd
hex8f25535

150099253 has 2 divisors, whose sum is σ = 150099254. Its totient is φ = 150099252.

The previous prime is 150099251. The next prime is 150099277. The reversal of 150099253 is 352990051.

It is a happy number.

150099253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135908964 + 14190289 = 11658^2 + 3767^2 .

It is a cyclic number.

It is not a de Polignac number, because 150099253 - 21 = 150099251 is a prime.

Together with 150099251, it forms a pair of twin primes.

It is the 12252-nd Hogben number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150099251) by changing a digit.

It is a nontrivial repunit in base 12251.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75049626 + 75049627.

It is an arithmetic number, because the mean of its divisors is an integer number (75049627).

Almost surely, 2150099253 is an apocalyptic number.

It is an amenable number.

150099253 is a deficient number, since it is larger than the sum of its proper divisors (1).

150099253 is an equidigital number, since it uses as much as digits as its factorization.

150099253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12150, while the sum is 34.

The square root of 150099253 is about 12251.5000306085. The cubic root of 150099253 is about 531.4464499206.

The spelling of 150099253 in words is "one hundred fifty million, ninety-nine thousand, two hundred fifty-three".