Base | Representation |
---|---|
bin | 1101111010100110011110… |
… | …1100011001011010000000 |
3 | 2000011201001002210010211101 |
4 | 3132221213230121122000 |
5 | 4001140221234400000 |
6 | 52312525055024144 |
7 | 3136263334231615 |
oct | 336514754313200 |
9 | 60151032703741 |
10 | 15300413200000 |
11 | 4969961409085 |
12 | 18713a550b054 |
13 | 86ca90831c16 |
14 | 3ac78885650c |
15 | 1b7eeb242e6a |
hex | dea67b19680 |
15300413200000 has 96 divisors (see below), whose sum is σ = 38099177395020. Its totient is φ = 6120165120000.
The previous prime is 15300413199947. The next prime is 15300413200019. The reversal of 15300413200000 is 231400351.
15300413200000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 6 ways, for example, as 2708078349376 + 12592334850624 = 1645624^2 + 3548568^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18725517 + ... + 19525516.
Almost surely, 215300413200000 is an apocalyptic number.
15300413200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
15300413200000 is an abundant number, since it is smaller than the sum of its proper divisors (22798764195020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15300413200000 is an frugal number, since it uses more digits than its factorization.
15300413200000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38251072 (or 38251040 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 19.
Adding to 15300413200000 its reverse (231400351), we get a palindrome (15300644600351).
The spelling of 15300413200000 in words is "fifteen trillion, three hundred billion, four hundred thirteen million, two hundred thousand".
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