Base | Representation |
---|---|
bin | 1000010000100111011110… |
… | …11001011000101010101110 |
3 | 2101022101020022210200000122 |
4 | 10020103233121120222232 |
5 | 4340041101330334000 |
6 | 102344010325324542 |
7 | 3553146331552505 |
oct | 410235731305256 |
9 | 71271208720018 |
10 | 18163138136750 |
11 | 5872a41a69a62 |
12 | 205417a266752 |
13 | a19a131a7a39 |
14 | 46b159da583c |
15 | 2176e90c4085 |
hex | 1084ef658aae |
18163138136750 has 64 divisors (see below), whose sum is σ = 34103619950400. Its totient is φ = 7243418160000.
The previous prime is 18163138136711. The next prime is 18163138136753. The reversal of 18163138136750 is 5763183136181.
It is a super-3 number, since 3×181631381367503 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 18163138136692 and 18163138136701.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (18163138136753) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1055803649 + ... + 1055820851.
It is an arithmetic number, because the mean of its divisors is an integer number (532869061725).
Almost surely, 218163138136750 is an apocalyptic number.
18163138136750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
18163138136750 is a deficient number, since it is larger than the sum of its proper divisors (15940481813650).
18163138136750 is a wasteful number, since it uses less digits than its factorization.
18163138136750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29670 (or 29660 counting only the distinct ones).
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 18163138136750 in words is "eighteen trillion, one hundred sixty-three billion, one hundred thirty-eight million, one hundred thirty-six thousand, seven hundred fifty".
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