Base | Representation |
---|---|
bin | 101101011101000111101100… |
… | …110001010101001100000000 |
3 | 222012211111222101102210121000 |
4 | 231131013230301111030000 |
5 | 202200334241114202021 |
6 | 1545102511235132000 |
7 | 60052153040245344 |
oct | 5535075461251400 |
9 | 865744871383530 |
10 | 199913225147136 |
11 | 587757a4961016 |
12 | 1a508632744000 |
13 | 87719756a15b7 |
14 | 3751bcd1b9624 |
15 | 181a305e2bb26 |
hex | b5d1ecc55300 |
199913225147136 has 144 divisors (see below), whose sum is σ = 600002138915200. Its totient is φ = 65643148403712.
The previous prime is 199913225147089. The next prime is 199913225147179. The reversal of 199913225147136 is 631741522319991.
199913225147136 is a `hidden beast` number, since 1 + 9 + 9 + 9 + 13 + 2 + 2 + 514 + 71 + 36 = 666.
It is a tau number, because it is divible by the number of its divisors (144).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 215377426 + ... + 216303633.
Almost surely, 2199913225147136 is an apocalyptic number.
199913225147136 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
199913225147136 is an abundant number, since it is smaller than the sum of its proper divisors (400088913768064).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
199913225147136 is an equidigital number, since it uses as much as digits as its factorization.
199913225147136 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 431681151 (or 431681131 counting only the distinct ones).
The product of its digits is 22044960, while the sum is 63.
The spelling of 199913225147136 in words is "one hundred ninety-nine trillion, nine hundred thirteen billion, two hundred twenty-five million, one hundred forty-seven thousand, one hundred thirty-six".
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