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200111221181 is a prime number
BaseRepresentation
bin1011101001011110001…
…1101110100110111101
3201010112002120022021102
42322113203232212331
511234311433034211
6231532501542445
720312641213004
oct2722743564675
9633462508242
10200111221181
1177959627333
1232948a14a25
1315b41391321
149984b93c3b
1553130e3a3b
hex2e978ee9bd

200111221181 has 2 divisors, whose sum is σ = 200111221182. Its totient is φ = 200111221180.

The previous prime is 200111221133. The next prime is 200111221183. The reversal of 200111221181 is 181122111002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 184277025625 + 15834195556 = 429275^2 + 125834^2 .

It is a cyclic number.

It is not a de Polignac number, because 200111221181 - 234 = 182931351997 is a prime.

It is a super-2 number, since 2×2001112211812 (a number of 23 digits) contains 22 as substring.

Together with 200111221183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200111221183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055610590 + 100055610591.

It is an arithmetic number, because the mean of its divisors is an integer number (100055610591).

Almost surely, 2200111221181 is an apocalyptic number.

It is an amenable number.

200111221181 is a deficient number, since it is larger than the sum of its proper divisors (1).

200111221181 is an equidigital number, since it uses as much as digits as its factorization.

200111221181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 20.

Adding to 200111221181 its reverse (181122111002), we get a palindrome (381233332183).

The spelling of 200111221181 in words is "two hundred billion, one hundred eleven million, two hundred twenty-one thousand, one hundred eighty-one".