Base | Representation |
---|---|
bin | 101101100000000001001000… |
… | …100101011100101001000000 |
3 | 222020112112220121221010010210 |
4 | 231200001020211130221000 |
5 | 202212120030003001144 |
6 | 1545334200453354120 |
7 | 60102432120655353 |
oct | 5540011045345100 |
9 | 866475817833123 |
10 | 200112334031424 |
11 | 58842189708851 |
12 | 1a53b13b938940 |
13 | 87876871b7b69 |
14 | 375b6babb429a |
15 | 18205ab02bab9 |
hex | b6004895ca40 |
200112334031424 has 56 divisors (see below), whose sum is σ = 529491879231040. Its totient is φ = 66700584359424.
The previous prime is 200112334031369. The next prime is 200112334031437. The reversal of 200112334031424 is 424130433211002.
It is a junction number, because it is equal to n+sod(n) for n = 200112334031391 and 200112334031400.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23912659 + ... + 31177554.
Almost surely, 2200112334031424 is an apocalyptic number.
200112334031424 is a gapful number since it is divisible by the number (24) formed by its first and last digit.
It is an amenable number.
200112334031424 is an abundant number, since it is smaller than the sum of its proper divisors (329379545199616).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200112334031424 is a wasteful number, since it uses less digits than its factorization.
200112334031424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55109147 (or 55109137 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 200112334031424 its reverse (424130433211002), we get a palindrome (624242767242426).
The spelling of 200112334031424 in words is "two hundred trillion, one hundred twelve billion, three hundred thirty-four million, thirty-one thousand, four hundred twenty-four".
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