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200141030112 = 2532084802397
BaseRepresentation
bin1011101001100101010…
…1011100001011100000
3201010121011122202102220
42322121111130023200
511234342100430422
6231535444511040
720313452454342
oct2723125341340
9633534582386
10200141030112
1177974437211
12329569ab480
1315b475ca34a
149988b13292
155315a30e5c
hex2e9955c2e0

200141030112 has 24 divisors (see below), whose sum is σ = 525370204296. Its totient is φ = 66713676672.

The previous prime is 200141030093. The next prime is 200141030213. The reversal of 200141030112 is 211030141002.

It is a tau number, because it is divible by the number of its divisors (24).

It is a junction number, because it is equal to n+sod(n) for n = 200141030091 and 200141030100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1042401103 + ... + 1042401294.

It is an arithmetic number, because the mean of its divisors is an integer number (21890425179).

Almost surely, 2200141030112 is an apocalyptic number.

It is an amenable number.

200141030112 is an abundant number, since it is smaller than the sum of its proper divisors (325229174184).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200141030112 is a wasteful number, since it uses less digits than its factorization.

200141030112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2084802410 (or 2084802402 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 200141030112 its reverse (211030141002), we get a palindrome (411171171114).

The spelling of 200141030112 in words is "two hundred billion, one hundred forty-one million, thirty thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 24 32 48 96 2084802397 4169604794 6254407191 8339209588 12508814382 16678419176 25017628764 33356838352 50035257528 66713676704 100070515056 200141030112