Base | Representation |
---|---|
bin | 11101001000000001100… |
… | …010010000000110011111 |
3 | 21002100011121200212002222 |
4 | 131020001202100012133 |
5 | 230243013003002444 |
6 | 4131244545335555 |
7 | 264413360453156 |
oct | 35100142200637 |
9 | 7070147625088 |
10 | 2001480515999 |
11 | 701906633428 |
12 | 283a979375bb |
13 | 11697b1c4043 |
14 | 6cc2d36059d |
15 | 370e2e78eee |
hex | 1d20189019f |
2001480515999 has 2 divisors, whose sum is σ = 2001480516000. Its totient is φ = 2001480515998.
The previous prime is 2001480515959. The next prime is 2001480516001. The reversal of 2001480515999 is 9995150841002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001480515999 - 28 = 2001480515743 is a prime.
It is a super-3 number, since 3×20014805159993 (a number of 38 digits) contains 333 as substring.
Together with 2001480516001, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2001480515999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001480515959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000740257999 + 1000740258000.
It is an arithmetic number, because the mean of its divisors is an integer number (1000740258000).
Almost surely, 22001480515999 is an apocalyptic number.
2001480515999 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001480515999 is an equidigital number, since it uses as much as digits as its factorization.
2001480515999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 53.
The spelling of 2001480515999 in words is "two trillion, one billion, four hundred eighty million, five hundred fifteen thousand, nine hundred ninety-nine".
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