Base | Representation |
---|---|
bin | 101101100010111010011101… |
… | …001001010111111010111000 |
3 | 222021020120112101110012200120 |
4 | 231202322131021113322320 |
5 | 202223400041213343112 |
6 | 1550005430043533240 |
7 | 60123005163156504 |
oct | 5542723511277270 |
9 | 867216471405616 |
10 | 200311321231032 |
11 | 58909610803030 |
12 | 1a57181422a220 |
13 | 87a037973775b |
14 | 3767196575304 |
15 | 18258555e1e8c |
hex | b62e9d257eb8 |
200311321231032 has 64 divisors (see below), whose sum is σ = 546304858473600. Its totient is φ = 60700260915840.
The previous prime is 200311321231009. The next prime is 200311321231081. The reversal of 200311321231032 is 230132123113002.
200311321231032 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a junction number, because it is equal to n+sod(n) for n = 200311321230993 and 200311321231011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 221535598 + ... + 222437954.
It is an arithmetic number, because the mean of its divisors is an integer number (8536013413650).
Almost surely, 2200311321231032 is an apocalyptic number.
200311321231032 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
200311321231032 is an abundant number, since it is smaller than the sum of its proper divisors (345993537242568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200311321231032 is a wasteful number, since it uses less digits than its factorization.
200311321231032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1743236 (or 1743232 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 200311321231032 its reverse (230132123113002), we get a palindrome (430443444344034).
The spelling of 200311321231032 in words is "two hundred trillion, three hundred eleven billion, three hundred twenty-one million, two hundred thirty-one thousand, thirty-two".
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