Base | Representation |
---|---|
bin | 101101110000000011010110… |
… | …010011011011111100101000 |
3 | 222101102220002011222210111010 |
4 | 231300003112103123330220 |
5 | 202333143212131134230 |
6 | 1551540312120503520 |
7 | 60245151013145565 |
oct | 5560032623337450 |
9 | 871386064883433 |
10 | 201214223302440 |
11 | 59127522457047 |
12 | 1a6987b831aba0 |
13 | 883755c50b37a |
14 | 3798b6b15186c |
15 | 183e09c7bb9b0 |
hex | b700d64dbf28 |
201214223302440 has 64 divisors (see below), whose sum is σ = 603788514033600. Its totient is φ = 53644162291712.
The previous prime is 201214223302427. The next prime is 201214223302447. The reversal of 201214223302440 is 44203322412102.
201214223302440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 201214223302398 and 201214223302407.
It is not an unprimeable number, because it can be changed into a prime (201214223302447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 202062537 + ... + 203055896.
It is an arithmetic number, because the mean of its divisors is an integer number (9434195531775).
Almost surely, 2201214223302440 is an apocalyptic number.
201214223302440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
201214223302440 is an abundant number, since it is smaller than the sum of its proper divisors (402574290731160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201214223302440 is a wasteful number, since it uses less digits than its factorization.
201214223302440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 405122586 (or 405122582 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 201214223302440 its reverse (44203322412102), we get a palindrome (245417545714542).
The spelling of 201214223302440 in words is "two hundred one trillion, two hundred fourteen billion, two hundred twenty-three million, three hundred two thousand, four hundred forty".
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