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20132112300 = 22352173947473
BaseRepresentation
bin10010101111111101…
…111010011110101100
31220222001010021020220
4102233331322132230
5312212310043200
613125405011340
71311615062646
oct225775723654
956861107226
1020132112300
1185a1063a43
123a9a253b50
131b8ab829b1
14d8da75896
157cc6654a0
hex4aff7a7ac

20132112300 has 72 divisors (see below), whose sum is σ = 61675333776. Its totient is φ = 5052764160.

The previous prime is 20132112293. The next prime is 20132112307. The reversal of 20132112300 is 321123102.

It is an interprime number because it is at equal distance from previous prime (20132112293) and next prime (20132112307).

It is a super-2 number, since 2×201321123002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 20132112300.

It is not an unprimeable number, because it can be changed into a prime (20132112307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1968637 + ... + 1978836.

It is an arithmetic number, because the mean of its divisors is an integer number (856601858).

Almost surely, 220132112300 is an apocalyptic number.

20132112300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

20132112300 is an abundant number, since it is smaller than the sum of its proper divisors (41543221476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20132112300 is a wasteful number, since it uses less digits than its factorization.

20132112300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3947507 (or 3947500 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 20132112300 its reverse (321123102), we get a palindrome (20453235402).

The spelling of 20132112300 in words is "twenty billion, one hundred thirty-two million, one hundred twelve thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 17 20 25 30 34 50 51 60 68 75 85 100 102 150 170 204 255 300 340 425 510 850 1020 1275 1700 2550 5100 3947473 7894946 11842419 15789892 19737365 23684838 39474730 47369676 59212095 67107041 78949460 98686825 118424190 134214082 197373650 201321123 236848380 268428164 296060475 335535205 394747300 402642246 592120950 671070410 805284492 1006605615 1184241900 1342140820 1677676025 2013211230 3355352050 4026422460 5033028075 6710704100 10066056150 20132112300