Base | Representation |
---|---|
bin | 1011101110000001100… |
… | …0110111100101010000 |
3 | 201020200020202202011100 |
4 | 2323200120313211100 |
5 | 11244312234023440 |
6 | 232254031144400 |
7 | 20355136131231 |
oct | 2734030674520 |
9 | 636606682140 |
10 | 201333111120 |
11 | 78426324329 |
12 | 3302a075100 |
13 | 15ca757b21b |
14 | 9a5d181088 |
15 | 5385505230 |
hex | 2ee0637950 |
201333111120 has 60 divisors (see below), whose sum is σ = 676143700596. Its totient is φ = 53688829440.
The previous prime is 201333111073. The next prime is 201333111149. The reversal of 201333111120 is 21111333102.
201333111120 is a `hidden beast` number, since 201 + 3 + 331 + 11 + 120 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 106059646224 + 95273464896 = 325668^2 + 308664^2 .
It is a tau number, because it is divible by the number of its divisors (60).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 201333111093 and 201333111102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 139813941 + ... + 139815380.
Almost surely, 2201333111120 is an apocalyptic number.
201333111120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
201333111120 is an abundant number, since it is smaller than the sum of its proper divisors (474810589476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201333111120 is a wasteful number, since it uses less digits than its factorization.
201333111120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 279629340 (or 279629331 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 201333111120 its reverse (21111333102), we get a palindrome (222444444222).
It can be divided in two parts, 20133 and 3111120, that added together give a triangular number (3131253 = T2502).
The spelling of 201333111120 in words is "two hundred one billion, three hundred thirty-three million, one hundred eleven thousand, one hundred twenty".
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