Base | Representation |
---|---|
bin | 10010110000001010… |
… | …111000000110011111 |
3 | 1220222021111220121121 |
4 | 102300022320012133 |
5 | 312214142313211 |
6 | 13130005511411 |
7 | 1311656005021 |
oct | 226012700637 |
9 | 56867456547 |
10 | 20135510431 |
11 | 85a2a75013 |
12 | 3a9b412567 |
13 | 1b8b7a261a |
14 | d902bc011 |
15 | 7ccad7271 |
hex | 4b02b819f |
20135510431 has 2 divisors, whose sum is σ = 20135510432. Its totient is φ = 20135510430.
The previous prime is 20135510429. The next prime is 20135510449. The reversal of 20135510431 is 13401553102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20135510431 - 21 = 20135510429 is a prime.
It is a super-2 number, since 2×201355104312 (a number of 21 digits) contains 22 as substring.
Together with 20135510429, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 20135510396 and 20135510405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20135510491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067755215 + 10067755216.
It is an arithmetic number, because the mean of its divisors is an integer number (10067755216).
Almost surely, 220135510431 is an apocalyptic number.
20135510431 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135510431 is an equidigital number, since it uses as much as digits as its factorization.
20135510431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 20135510431 in words is "twenty billion, one hundred thirty-five million, five hundred ten thousand, four hundred thirty-one".
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