Base | Representation |
---|---|
bin | 110000000000011000111011… |
… | …011111000011001011100000 |
3 | 1000200120010011210212122021001 |
4 | 300000120323133003023200 |
5 | 210133200341041111000 |
6 | 2025013054503441344 |
7 | 62320566366623125 |
oct | 6000307337031340 |
9 | 1020503153778231 |
10 | 211133000332000 |
11 | 6130100350920a |
12 | 1b81aba6756254 |
13 | 90a69ab057126 |
14 | 3a1cc6ad1674c |
15 | 19620c1bb946a |
hex | c0063b7c32e0 |
211133000332000 has 96 divisors (see below), whose sum is σ = 520820532427104. Its totient is φ = 84116732800000.
The previous prime is 211133000331989. The next prime is 211133000332039. The reversal of 211133000332000 is 233000331112.
It is a super-2 number, since 2×2111330003320002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 104141917 + ... + 106149916.
It is an arithmetic number, because the mean of its divisors is an integer number (5425213879449).
Almost surely, 2211133000332000 is an apocalyptic number.
211133000332000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211133000332000 is an abundant number, since it is smaller than the sum of its proper divisors (309687532095104).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211133000332000 is a wasteful number, since it uses less digits than its factorization.
211133000332000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210292109 (or 210292091 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 211133000332000 its reverse (233000331112), we get a palindrome (211366000663112).
The spelling of 211133000332000 in words is "two hundred eleven trillion, one hundred thirty-three billion, three hundred thirty-two thousand".
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