Base | Representation |
---|---|
bin | 1100010010110111000… |
… | …0001101101101101110 |
3 | 202012012100121010020220 |
4 | 3010231300031231232 |
5 | 11430040034330220 |
6 | 241011131152210 |
7 | 21155152654461 |
oct | 3045560155556 |
9 | 665170533226 |
10 | 211221011310 |
11 | 8163a833071 |
12 | 34b295a5666 |
13 | 16bc1c7963a |
14 | a31a4832d8 |
15 | 576361d540 |
hex | 312dc0db6e |
211221011310 has 64 divisors (see below), whose sum is σ = 529162813440. Its totient is φ = 53896170240.
The previous prime is 211221011299. The next prime is 211221011333. The reversal of 211221011310 is 13110122112.
It is a super-2 number, since 2×2112210113102 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 211221011310.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1193182 + ... + 1358721.
It is an arithmetic number, because the mean of its divisors is an integer number (8268168960).
Almost surely, 2211221011310 is an apocalyptic number.
211221011310 is an abundant number, since it is smaller than the sum of its proper divisors (317941802130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211221011310 is a wasteful number, since it uses less digits than its factorization.
211221011310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2552033.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 211221011310 its reverse (13110122112), we get a palindrome (224331133422).
The spelling of 211221011310 in words is "two hundred eleven billion, two hundred twenty-one million, eleven thousand, three hundred ten".
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