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2112211031100 = 2235248869144073
BaseRepresentation
bin11110101111001001100…
…101101001010000111100
321110220222121200211210220
4132233021211221100330
5234101302010443400
64254200352501340
7305413362350232
oct36571145512074
97426877624726
102112211031100
11744869075325
122a143b24a850
13124246b558b1
1474335582952
1539e242707a0
hex1ebc996943c

2112211031100 has 72 divisors (see below), whose sum is σ = 6111498057840. Its totient is φ = 563240839680.

The previous prime is 2112211031093. The next prime is 2112211031107. The reversal of 2112211031100 is 11301122112.

It is an interprime number because it is at equal distance from previous prime (2112211031093) and next prime (2112211031107).

It is a super-2 number, since 2×21122110311002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 2112211031100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112211031107) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14588664 + ... + 14732736.

It is an arithmetic number, because the mean of its divisors is an integer number (84881917470).

Almost surely, 22112211031100 is an apocalyptic number.

2112211031100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2112211031100 is an abundant number, since it is smaller than the sum of its proper divisors (3999287026740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2112211031100 is a wasteful number, since it uses less digits than its factorization.

2112211031100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192959 (or 192952 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 2112211031100 its reverse (11301122112), we get a palindrome (2123512153212).

The spelling of 2112211031100 in words is "two trillion, one hundred twelve billion, two hundred eleven million, thirty-one thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 300 48869 97738 144073 146607 195476 244345 288146 293214 432219 488690 576292 586428 720365 733035 864438 977380 1221725 1440730 1466070 1728876 2161095 2443450 2881460 2932140 3601825 3665175 4322190 4886900 7203650 7330350 8644380 10805475 14407300 14660700 21610950 43221900 7040703437 14081406874 21122110311 28162813748 35203517185 42244220622 70407034370 84488441244 105610551555 140814068740 176017585925 211221103110 352035171850 422442206220 528052757775 704070343700 1056105515550 2112211031100