Base | Representation |
---|---|
bin | 110000000011010000011111… |
… | …110011110100011111000000 |
3 | 1000201020221221100011100022121 |
4 | 300003100133303310133000 |
5 | 210144413023223313100 |
6 | 2025243413150214024 |
7 | 62341044665531431 |
oct | 6003203763643700 |
9 | 1021227840140277 |
10 | 211330104510400 |
11 | 613776596a4817 |
12 | 1b8512344b4314 |
13 | 90bc4604393a5 |
14 | 3a2860858d488 |
15 | 19672aacc751a |
hex | c0341fcf47c0 |
211330104510400 has 84 divisors (see below), whose sum is σ = 521398252854952. Its totient is φ = 84305414108160.
The previous prime is 211330104510397. The next prime is 211330104510461. The reversal of 211330104510400 is 4015401033112.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 176455902 + ... + 177649501.
Almost surely, 2211330104510400 is an apocalyptic number.
211330104510400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211330104510400 is an abundant number, since it is smaller than the sum of its proper divisors (310068148344552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211330104510400 is a wasteful number, since it uses less digits than its factorization.
211330104510400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354105798 (or 354105783 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 211330104510400 its reverse (4015401033112), we get a palindrome (215345505543512).
The spelling of 211330104510400 in words is "two hundred eleven trillion, three hundred thirty billion, one hundred four million, five hundred ten thousand, four hundred".
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