Base | Representation |
---|---|
bin | 1100010011100100011… |
… | …0001100110011101100 |
3 | 202012200121201000101020 |
4 | 3010321012030303230 |
5 | 11430432244333030 |
6 | 241042050214140 |
7 | 21162653414412 |
oct | 3047106146354 |
9 | 665617630336 |
10 | 211411324140 |
11 | 817281a99a5 |
12 | 34b81284350 |
13 | 16c22521593 |
14 | a3378632b2 |
15 | 57751b2510 |
hex | 313918ccec |
211411324140 has 48 divisors (see below), whose sum is σ = 612363840480. Its totient is φ = 54432340480.
The previous prime is 211411324133. The next prime is 211411324231. The reversal of 211411324140 is 41423114112.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 211411324140.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60748641 + ... + 60752120.
It is an arithmetic number, because the mean of its divisors is an integer number (12757580010).
Almost surely, 2211411324140 is an apocalyptic number.
211411324140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211411324140 is an abundant number, since it is smaller than the sum of its proper divisors (400952516340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211411324140 is a wasteful number, since it uses less digits than its factorization.
211411324140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121500802 (or 121500800 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 211411324140 its reverse (41423114112), we get a palindrome (252834438252).
The spelling of 211411324140 in words is "two hundred eleven billion, four hundred eleven million, three hundred twenty-four thousand, one hundred forty".
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