Base | Representation |
---|---|
bin | 110000010011011101000101… |
… | …010100000010001111010010 |
3 | 1000212012100212000102211122010 |
4 | 300103131011110002033102 |
5 | 210321132012320221002 |
6 | 2031455005434323350 |
7 | 62514336545254032 |
oct | 6023350524021722 |
9 | 1025170760384563 |
10 | 212443130242002 |
11 | 61766697705750 |
12 | 1b9b0a9a589556 |
13 | 91703bba2554a |
14 | 3a6643399d8c2 |
15 | 19862000ae46c |
hex | c137455023d2 |
212443130242002 has 64 divisors (see below), whose sum is σ = 487915505418240. Its totient is φ = 60987478708800.
The previous prime is 212443130241997. The next prime is 212443130242019. The reversal of 212443130242002 is 200242031344212.
It is a super-3 number, since 3×2124431302420023 (a number of 44 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78604852 + ... + 81262592.
It is an arithmetic number, because the mean of its divisors is an integer number (7623679772160).
Almost surely, 2212443130242002 is an apocalyptic number.
212443130242002 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
212443130242002 is an abundant number, since it is smaller than the sum of its proper divisors (275472375176238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212443130242002 is a wasteful number, since it uses less digits than its factorization.
212443130242002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2721519.
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 212443130242002 its reverse (200242031344212), we get a palindrome (412685161586214).
The spelling of 212443130242002 in words is "two hundred twelve trillion, four hundred forty-three billion, one hundred thirty million, two hundred forty-two thousand, two".
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