Search a number
-
+
213132013013300 = 22525340213587361
BaseRepresentation
bin110000011101011110101001…
…111011010000100100110100
31000221122012222102220111120212
4300131132221323100210310
5210413423330312411200
62033143254535044552
762615164653225053
oct6035365173204464
91027565872814525
10213132013013300
1161a01863007927
121baa24b3b10758
1391c0354ba1444
143a8b9045da39a
1519990bd16d035
hexc1d7a9ed0934

213132013013300 has 36 divisors (see below), whose sum is σ = 471222816707916. Its totient is φ = 83644261708800.

The previous prime is 213132013013237. The next prime is 213132013013321. The reversal of 213132013013300 is 3310310231312.

213132013013300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 6 ways, for example, as 28195186687396 + 184936826325904 = 5309914^2 + 13599148^2 .

It is a super-2 number, since 2×2131320130133002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20106788381 + ... + 20106798980.

It is an arithmetic number, because the mean of its divisors is an integer number (13089522686331).

Almost surely, 2213132013013300 is an apocalyptic number.

213132013013300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

213132013013300 is an abundant number, since it is smaller than the sum of its proper divisors (258090803694616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213132013013300 is a wasteful number, since it uses less digits than its factorization.

213132013013300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40213587428 (or 40213587421 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 213132013013300 its reverse (3310310231312), we get a palindrome (216442323244612).

The spelling of 213132013013300 in words is "two hundred thirteen trillion, one hundred thirty-two billion, thirteen million, thirteen thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 53 100 106 212 265 530 1060 1325 2650 5300 40213587361 80427174722 160854349444 201067936805 402135873610 804271747220 1005339684025 2010679368050 2131320130133 4021358736100 4262640260266 8525280520532 10656600650665 21313201301330 42626402602660 53283003253325 106566006506650 213132013013300