Base | Representation |
---|---|
bin | 1001110011011101000010… |
… | …10010010111001000000000 |
3 | 2211100000221000020120212000 |
4 | 10321232201102113020000 |
5 | 10311211113040204322 |
6 | 113504045121104000 |
7 | 4353411520132260 |
oct | 471564122271000 |
9 | 84300830216760 |
10 | 21559146803712 |
11 | 6962201363491 |
12 | 2502382788000 |
13 | c0503246a43b |
14 | 54767ad257a0 |
15 | 275c09aee3ac |
hex | 139ba1497200 |
21559146803712 has 160 divisors (see below), whose sum is σ = 72933225129600. Its totient is φ = 6159756201984.
The previous prime is 21559146803669. The next prime is 21559146803759. The reversal of 21559146803712 is 21730864195512.
21559146803712 is a `hidden beast` number, since 2 + 1 + 5 + 59 + 146 + 80 + 371 + 2 = 666.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 111299287 + ... + 111492822.
It is an arithmetic number, because the mean of its divisors is an integer number (455832657060).
It is a 1-persistent number, because it is pandigital, but 2⋅21559146803712 = 43118293607424 is not.
Almost surely, 221559146803712 is an apocalyptic number.
It is an amenable number.
21559146803712 is an abundant number, since it is smaller than the sum of its proper divisors (51374078325888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21559146803712 is an equidigital number, since it uses as much as digits as its factorization.
21559146803712 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222792143 (or 222792121 counting only the distinct ones).
The product of its (nonzero) digits is 3628800, while the sum is 54.
The spelling of 21559146803712 in words is "twenty-one trillion, five hundred fifty-nine billion, one hundred forty-six million, eight hundred three thousand, seven hundred twelve".
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