Base | Representation |
---|---|
bin | 100001101001100111101… |
… | …000111111011011000000 |
3 | 22012001210022021110210100 |
4 | 201221213220333123000 |
5 | 300341324342012112 |
6 | 4530152150002400 |
7 | 326032125630645 |
oct | 41514750773300 |
9 | 8161708243710 |
10 | 2312431204032 |
11 | 811773147724 |
12 | 3141b8646400 |
13 | 13a0a49730c1 |
14 | 7dcca9b7dcc |
15 | 40241bd62dc |
hex | 21a67a3f6c0 |
2312431204032 has 84 divisors (see below), whose sum is σ = 6652806994080. Its totient is φ = 767944883712.
The previous prime is 2312431204009. The next prime is 2312431204037. The reversal of 2312431204032 is 2304021342132.
2312431204032 is a `hidden beast` number, since 2 + 3 + 1 + 243 + 12 + 0 + 403 + 2 = 666.
2312431204032 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 2312431203987 and 2312431204005.
It is not an unprimeable number, because it can be changed into a prime (2312431204037) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7307208 + ... + 7617095.
Almost surely, 22312431204032 is an apocalyptic number.
It is an amenable number.
2312431204032 is an abundant number, since it is smaller than the sum of its proper divisors (4340375790048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2312431204032 is a wasteful number, since it uses less digits than its factorization.
2312431204032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14924590 (or 14924577 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 2312431204032 its reverse (2304021342132), we get a palindrome (4616452546164).
The spelling of 2312431204032 in words is "two trillion, three hundred twelve billion, four hundred thirty-one million, two hundred four thousand, thirty-two".
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