Base | Representation |
---|---|
bin | 1101100101011111110… |
… | …1101001011111010100 |
3 | 211022110022211100011120 |
4 | 3121113331221133110 |
5 | 12311002411400000 |
6 | 255120242003540 |
7 | 22601653241361 |
oct | 3312775513724 |
9 | 738408740146 |
10 | 233404012500 |
11 | 8aa935311aa |
12 | 3929a6465b0 |
13 | 190189b3549 |
14 | b42265d468 |
15 | 6110d496a0 |
hex | 3657f697d4 |
233404012500 has 72 divisors (see below), whose sum is σ = 680718243744. Its totient is φ = 62241060000.
The previous prime is 233404012469. The next prime is 233404012553. The reversal of 233404012500 is 5210404332.
It is a super-2 number, since 2×2334040125002 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3074554 + ... + 3149553.
It is an arithmetic number, because the mean of its divisors is an integer number (9454420052).
Almost surely, 2233404012500 is an apocalyptic number.
233404012500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
233404012500 is an abundant number, since it is smaller than the sum of its proper divisors (447314231244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
233404012500 is an equidigital number, since it uses as much as digits as its factorization.
233404012500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6224139 (or 6224117 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 24.
Adding to 233404012500 its reverse (5210404332), we get a palindrome (238614416832).
The spelling of 233404012500 in words is "two hundred thirty-three billion, four hundred four million, twelve thousand, five hundred".
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