Base | Representation |
---|---|
bin | 1110001010100100000… |
… | …1111001010110010000 |
3 | 212021010202111211210010 |
4 | 3202221001321112100 |
5 | 12441342111440440 |
6 | 303443441034520 |
7 | 23403352666356 |
oct | 3425101712620 |
9 | 767122454703 |
10 | 243354015120 |
11 | 94229aa7467 |
12 | 3b1b6925a40 |
13 | 19c43216868 |
14 | bac7cc97d6 |
15 | 64e462d580 |
hex | 38a9079590 |
243354015120 has 80 divisors (see below), whose sum is σ = 778732872192. Its totient is φ = 62801034240.
The previous prime is 243354015067. The next prime is 243354015131. The reversal of 243354015120 is 21510453342.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-3 number, since 3×2433540151203 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16346997 + ... + 16361876.
Almost surely, 2243354015120 is an apocalyptic number.
243354015120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
243354015120 is an abundant number, since it is smaller than the sum of its proper divisors (535378857072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
243354015120 is a wasteful number, since it uses less digits than its factorization.
243354015120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32708920 (or 32708914 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 243354015120 its reverse (21510453342), we get a palindrome (264864468462).
The spelling of 243354015120 in words is "two hundred forty-three billion, three hundred fifty-four million, fifteen thousand, one hundred twenty".
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