Base | Representation |
---|---|
bin | 1011000100011110111100… |
… | …11011011110110000000110 |
3 | 10012012012100020010221102220 |
4 | 11202033132123132300012 |
5 | 11142320100210142410 |
6 | 123435055103113210 |
7 | 5061513643624266 |
oct | 542173633366006 |
9 | 105165306127386 |
10 | 24343311412230 |
11 | 7835a38732a68 |
12 | 2891a918a2806 |
13 | 107774503a235 |
14 | 6023189b77a6 |
15 | 2c335aa91070 |
hex | 1623de6dec06 |
24343311412230 has 32 divisors (see below), whose sum is σ = 60964119016704. Its totient is φ = 6209308418016.
The previous prime is 24343311412187. The next prime is 24343311412247. The reversal of 24343311412230 is 3221411334342.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 24343311412191 and 24343311412200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17640080044 + ... + 17640081423.
It is an arithmetic number, because the mean of its divisors is an integer number (1905128719272).
Almost surely, 224343311412230 is an apocalyptic number.
24343311412230 is an abundant number, since it is smaller than the sum of its proper divisors (36620807604474).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
24343311412230 is a wasteful number, since it uses less digits than its factorization.
24343311412230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35280161500.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 24343311412230 its reverse (3221411334342), we get a palindrome (27564722746572).
The spelling of 24343311412230 in words is "twenty-four trillion, three hundred forty-three billion, three hundred eleven million, four hundred twelve thousand, two hundred thirty".
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