Base | Representation |
---|---|
bin | 100011100000100001010… |
… | …100101101011100110100 |
3 | 22122021022210120202022202 |
4 | 203200201110231130310 |
5 | 304434311212020200 |
6 | 5104544450044032 |
7 | 341201652020420 |
oct | 43404124553464 |
9 | 8567283522282 |
10 | 2440100501300 |
11 | 860928135350 |
12 | 334aa8879618 |
13 | 14913ca12997 |
14 | 8615c701b80 |
15 | 437151111d5 |
hex | 2382152d734 |
2440100501300 has 144 divisors (see below), whose sum is σ = 6726140249472. Its totient is φ = 746200665600.
The previous prime is 2440100501291. The next prime is 2440100501389. The reversal of 2440100501300 is 31050010442.
It is a super-2 number, since 2×24401005013002 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2581487 + ... + 3397686.
It is an arithmetic number, because the mean of its divisors is an integer number (46709307288).
Almost surely, 22440100501300 is an apocalyptic number.
2440100501300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2440100501300 is an abundant number, since it is smaller than the sum of its proper divisors (4286039748172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2440100501300 is a wasteful number, since it uses less digits than its factorization.
2440100501300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5979258 (or 5979251 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 20.
Adding to 2440100501300 its reverse (31050010442), we get a palindrome (2471150511742).
The spelling of 2440100501300 in words is "two trillion, four hundred forty billion, one hundred million, five hundred one thousand, three hundred".
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