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2443313014130 = 25571427900703
BaseRepresentation
bin100011100011100000110…
…011011110010101110010
322122120121200111022110102
4203203200303132111302
5310012401112423010
65110235325232402
7341344400644142
oct43434063362562
98576550438412
102443313014130
1186222655482a
12335644702702
13149532442a51
1486385226922
1543852181ba5
hex238e0cde572

2443313014130 has 16 divisors (see below), whose sum is σ = 4405665648384. Its totient is φ = 975613600560.

The previous prime is 2443313014111. The next prime is 2443313014193. The reversal of 2443313014130 is 314103133442.

It is a happy number.

2443313014130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2443313014093 and 2443313014102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213944642 + ... + 213956061.

It is an arithmetic number, because the mean of its divisors is an integer number (275354103024).

Almost surely, 22443313014130 is an apocalyptic number.

2443313014130 is a deficient number, since it is larger than the sum of its proper divisors (1962352634254).

2443313014130 is a wasteful number, since it uses less digits than its factorization.

2443313014130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 427901281.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 2443313014130 its reverse (314103133442), we get a palindrome (2757416147572).

The spelling of 2443313014130 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, fourteen thousand, one hundred thirty".

Divisors: 1 2 5 10 571 1142 2855 5710 427900703 855801406 2139503515 4279007030 244331301413 488662602826 1221656507065 2443313014130