Base | Representation |
---|---|
bin | 100100101110110010000… |
… | …111001000000101100010 |
3 | 22221022020020110120101020 |
4 | 210232302013020011202 |
5 | 312323411301442310 |
6 | 5211323211550310 |
7 | 350235252061224 |
oct | 44566207100542 |
9 | 8838206416336 |
10 | 2524134015330 |
11 | 89352a9361a4 |
12 | 34923b45b396 |
13 | 1540426a1795 |
14 | 8a251036414 |
15 | 459d2775170 |
hex | 24bb21c8162 |
2524134015330 has 32 divisors (see below), whose sum is σ = 6414269969664. Its totient is φ = 633508144896.
The previous prime is 2524134015311. The next prime is 2524134015331. The reversal of 2524134015330 is 335104314252.
It is a junction number, because it is equal to n+sod(n) for n = 2524134015291 and 2524134015300.
It is not an unprimeable number, because it can be changed into a prime (2524134015331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2474640682 + ... + 2474641701.
It is an arithmetic number, because the mean of its divisors is an integer number (200445936552).
Almost surely, 22524134015330 is an apocalyptic number.
2524134015330 is an abundant number, since it is smaller than the sum of its proper divisors (3890135954334).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2524134015330 is a wasteful number, since it uses less digits than its factorization.
2524134015330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4949282410.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 2524134015330 its reverse (335104314252), we get a palindrome (2859238329582).
The spelling of 2524134015330 in words is "two trillion, five hundred twenty-four billion, one hundred thirty-four million, fifteen thousand, three hundred thirty".
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