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2553433 is a prime number
BaseRepresentation
bin1001101111011001011001
311210201122121
421233121121
51123202213
6130421241
730463261
oct11573131
94721577
102553433
111494483
12a31821
136b530c
144a67a1
1535688d
hex26f659

2553433 has 2 divisors, whose sum is σ = 2553434. Its totient is φ = 2553432.

The previous prime is 2553431. The next prime is 2553457. The reversal of 2553433 is 3343552.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2286144 + 267289 = 1512^2 + 517^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553433 - 21 = 2553431 is a prime.

Together with 2553431, it forms a pair of twin primes.

It is a d-powerful number, because it can be written as 215 + 5 + 59 + 33 + 47 + 39 + 312 .

It is a plaindrome in base 15.

It is a junction number, because it is equal to n+sod(n) for n = 2553398 and 2553407.

It is not a weakly prime, because it can be changed into another prime (2553431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276716 + 1276717.

It is an arithmetic number, because the mean of its divisors is an integer number (1276717).

22553433 is an apocalyptic number.

It is an amenable number.

2553433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553433 is an equidigital number, since it uses as much as digits as its factorization.

2553433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 25.

The square root of 2553433 is about 1597.9464947238. The cubic root of 2553433 is about 136.6810025282.

Adding to 2553433 its reverse (3343552), we get a palindrome (5896985).

The spelling of 2553433 in words is "two million, five hundred fifty-three thousand, four hundred thirty-three".