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2688894071 is a prime number
BaseRepresentation
bin1010000001000101…
…0100010001110111
320221101121222020022
42200101110101313
521001324102241
61122452155355
7123430136213
oct24021242167
96841558208
102688894071
11115a8a0a06
12630608b5b
1333b0c86a6
141b7181943
1510b0de54b
hexa0454477

2688894071 has 2 divisors, whose sum is σ = 2688894072. Its totient is φ = 2688894070.

The previous prime is 2688894067. The next prime is 2688894073. The reversal of 2688894071 is 1704988862.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2688894071 - 22 = 2688894067 is a prime.

It is a super-3 number, since 3×26888940713 (a number of 29 digits) contains 333 as substring.

Together with 2688894073, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2688894073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1344447035 + 1344447036.

It is an arithmetic number, because the mean of its divisors is an integer number (1344447036).

Almost surely, 22688894071 is an apocalyptic number.

2688894071 is a deficient number, since it is larger than the sum of its proper divisors (1).

2688894071 is an equidigital number, since it uses as much as digits as its factorization.

2688894071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1548288, while the sum is 53.

The square root of 2688894071 is about 51854.5472547972. The cubic root of 2688894071 is about 1390.5647983372.

The spelling of 2688894071 in words is "two billion, six hundred eighty-eight million, eight hundred ninety-four thousand, seventy-one".